Question

Convert -1 +√3i in polar form

Answer 1

Answer:

$2e^{i2\pi /3}$

Step-by-step explanation:

Given complex number

$-1+i\sqrt{3}$

Multiply and divide by 2

=$2(\frac{-1}{2}+i\frac{\sqrt{3}}2} )$

-1/2 is cos2π/3 and √3/2 is sin 2π/3

∴ $2(cos2\pi /3+i sin2\pi /3)$

in eulers or polar form it can be written as $2e^{i2\pi /3}$

Hope it helps

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