Question

convert -1 +i to polar form
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Answer 1

i given u the sollu tini you should followme

Answer 2

Answer:

-1 +i = r (cosθ + i sinθ)

rcosθ = -1

rsinθ = 1

r² (cos²θ + sin²θ) =  1 + 1

                          r² = 2

                          r = ±√2

tanθ = -1

tanθ = tan ( 180° - 45°)     (Since it lies in the II quadrant)

tanθ = tan135° = tan3π/4

θ = 3π/4

polar form = √2(cos3π/4+isin3π/4)