Convert 1 newton into dyne using dimensional analysis
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Dimensional formula of Force F [M1 L1 T-2]
So a =1, b=1, c=-2
Now because Newton is in m.k.s system,We Have.
M1 = 1kg, L1 = 1m, T1 = 1s
M2 = 1g, L2 = 1cm, T2 = 1s
n1= 1 Newton
n2 = ?
Using the formula
n2= n1[M1/M2]a [L1/L2]b [T1/T2]c
n2= 1 [1kg/1g]1 [1m/1cm]1 [1s/1s]-2
n2= 1[1000g/1g]1 [100cm/1cm]1 x1
n2= 1000×100 = 100000
= 105 dynes
So a =1, b=1, c=-2
Now because Newton is in m.k.s system,We Have.
M1 = 1kg, L1 = 1m, T1 = 1s
M2 = 1g, L2 = 1cm, T2 = 1s
n1= 1 Newton
n2 = ?
Using the formula
n2= n1[M1/M2]a [L1/L2]b [T1/T2]c
n2= 1 [1kg/1g]1 [1m/1cm]1 [1s/1s]-2
n2= 1[1000g/1g]1 [100cm/1cm]1 x1
n2= 1000×100 = 100000
= 105 dynes
jagmanpal42:
Excuse me, care to explain why my answer was deleted while being claimed that it was wrong...........
I'll let you know that it was correct. Besides I learnt this formula last year and I am confident in my skills.
Answered by
1
Answer:
Explanation:
Dimensional formula of Force F [M1 L1 T-2]
So a =1, b=1, c=-2
Now because Newton is in m.k.s system,We Have.
M1 = 1kg, L1 = 1m, T1 = 1s
M2 = 1g, L2 = 1cm, T2 = 1s
n1= 1 Newton
n2 = ?
Using the formula
n2= n1[M1/M2]a [L1/L2]b [T1/T2]c
n2= 1 [1kg/1g]1 [1m/1cm]1 [1s/1s]-2
n2= 1[1000g/1g]1 [100cm/1cm]1 x1
n2= 1000×100 = 100000
= 105 dynes
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