Question

convert -4 in polarform​

Answer 1

Answer:

z=−3+0i

putting

−3=rcosθ,0=rsinθ

9+0=r²

(sin²θ+cos²θ)r²

=9

r=3

$\frac{rsinθ}{rcosθ}$→$\frac{0}{-3}$

tanθ=0

θ=0

So, ∣z∣=3, argument of z=0

Therefore, polar form of z is

z=r(cosθ+isinθ)

=3(cos0 ∘ +isin0° )