Question

convert benzamide to aniline

Answer 1

This reaction is also known as Hoffmann bromamide reaction.here se the attachment and then you will get your answer

Answer 2

Conversion of benzamide to aniline:

$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CONH}_{2}+\mathrm{Br}_{2}+4 \mathrm{NaOH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+\mathrm{Na}_{2} \mathrm{CO}_{3}+2 \mathrm{NaBr}+2 \mathrm{H}_{2} \mathrm{O}$

We can change benzamide to aniline by Hoffmann bromamide reaction. In this, primary amide to a primary amine has one carbon atom less than the original amide on heating with mixture of Br₂ in the existence of NaOH or KOH (i.e. NaOBr or KOBr) is called Hofmann bromamide reaction. We can get the aniline in these steps.

We can get the aniline in these steps.

1. Decarboxylation of benzoic acid that gives us benzene.

2. $C_{6} H_{5} \mathrm{COOH}+\mathrm{CaO} \text { And } \mathrm{NaOH} \text { gives } C_{6} H_{6}$

3. Then nitration of benzene is done by adding concentrate $HNO_3$ and concentrate $H_2 SO_4$ that produces $C_6 H_5 NO_2$.

4. Then reduction with Sn/HCl or any other reducing agent will produce $C_6 H_5 NH_2$ (aniline).

Learn more about Hofmann bromamide reaction

Hofmann bromamide rection

https://brainly.in/question/9191698

Which compound undergoes hofmann bromamide reaction?

https://brainly.in/question/7927363