convert ethylene oxide to n-propyl alcohol
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CH2=CH2(ehtylene) on treating with Br2and CCl4gives BrCH2-CH2Br(Ethylene dibromide).
On treatingethylene dibromidewith NaNH2or Liq.NH3at 196 K, you get HC=CH(acetylene). This process is calleddehydrobromination reaction.
On treating this acetylene again with NaNH2 in liq. NH3 at 196 K, you get HC=C-Na+ (Sodium acetylide).
on treating this sodium acetylide with CH3I, NaI gets removed and you get HC=C-CH3 (Propyne).
now, he only have to convert triple bond into double bond . for this reducepropyne using H2-Pd/BaSO4. You get H2C=CH-CH3
(Propylene) . All you have to now do is to do an anti-markovnikov addition using H20 in the presence of H2O2to yield n-PROPYL ALCOHOL.
Hope u got ur answer
On treatingethylene dibromidewith NaNH2or Liq.NH3at 196 K, you get HC=CH(acetylene). This process is calleddehydrobromination reaction.
On treating this acetylene again with NaNH2 in liq. NH3 at 196 K, you get HC=C-Na+ (Sodium acetylide).
on treating this sodium acetylide with CH3I, NaI gets removed and you get HC=C-CH3 (Propyne).
now, he only have to convert triple bond into double bond . for this reducepropyne using H2-Pd/BaSO4. You get H2C=CH-CH3
(Propylene) . All you have to now do is to do an anti-markovnikov addition using H20 in the presence of H2O2to yield n-PROPYL ALCOHOL.
Hope u got ur answer
mansigupta23:
you use ethylene but in this question use of ethylene oxide
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