Question

convert the complex number 1 + 7i / (2 - i)^2 in polar form​

Answer 1

Answer:

Let z = 1+7i/(2-1)²

Using (a-b)² = a² + b² - 2ab

=(1 + 7i)/2² + i² - 2 x 2 x i

= 1 + 7i / 4 + i² - 4i

Putting i² = -1

= 1 + 7i/ 4 + (-1) - 4i

= 1 + 7i/ 4 -1 - 4i

= 1 - 7i/3-4i

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Step-by-step explanation:

Answer 2

Answer:

Let z = 1+7i/(2-1)²

Using (a-b)² = a² + b² - 2ab

=(1 + 7i)/2² + i² - 2 x 2 x i

= 1 + 7i / 4 + i² - 4i

Putting i² = -1

= 1 + 7i/ 4 + (-1) - 4i

= 1 + 7i/ 4 -1 - 4i

= 1 - 7i/3-4i

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Step-by-step explanation: