Question

convert the following products into factorials 1.3.5.7.9...2n-1​

Answer 1

1.3.5.7.9....(2n-1) = 1.2.3.4.5......(2n -1) / 2.4.6.8 ...... (2n -2)

Multiplying and dividing by 2.4.6 ... (2n -2)

= (2n -1) ! / 2^(n-1) ( 1.2.3.4......(n-1) )

taking 2 common from each term of denominator

= (2n - 1)! /[2^(n-1)(n-1)! ]

also you can multiply by 2n and divide by 2n to get

[(2n) !] / [2^n n!]

Hope it will help you..