cooling rate of sphere of 600K at external environment (200K) is R. when the temperature of sphere is reduced to 400K then cooling rate of the sphere becomes
Answers
Answered by
64
Answer :
Cooling rate of the sphere becomes
Step by Step Explanation :
Rate of cooling ∝ (T⁴-T₀⁴) Þ
=> (
=> H′ =
=>
Answered by
0
Explanation:
Cooling rate of the sphere becomes \frac{3}{16} H
16
3
H
Step by Step Explanation :
Rate of cooling ∝ (T⁴-T₀⁴) Þ \frac{H}{H'}
H
′
H
=> (\frac{T^{4}_{1} -T^{4}_{0}}{T^{4}_{2}-T^{4}_{0}}=\frac{400^{4}-200^{4}}{600^{4}-200^{4}}
T
2
4
−T
0
4
T
1
4
−T
0
4
=
600
4
−200
4
400
4
−200
4
=> H′ = \frac{ (16+4)(16-4)H}{(36+4)(36-4)}
(36+4)(36−4)
(16+4)(16−4)H
=> \frac{3}{16} H
16
3
H
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