Question

Coordinate Geometry.. answer fast

Answer 1

Let P(2y,y) Q(2,-5) R(-3,6)
A.T.Q
QP =PR
squaring both sides
(2y-2)^2 +(y+5)^2=(-3-2y)^2 +(6-y)^2
4+4y^2-8y +25+y^2+10y=9+4y^2+12y+36+y^2-12y
5y^2+2y+29=5y^2+45
2y=45-29
2y=16
y=8

P(16,8)

Answer 2

Answer:

The coordinates of point P is (16,8)

Refer attachment for solution

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