Question

Coordinates of the focus of the parabola x^2-4x-8y-4=0 are

Answer 1

Answer:

sorry Dodds FC's dz dz CD's deeded

Answer 2

The focus of the parabola is (2,1).

Step-by-step explanation:

Consider the provided equation of parabola.

$x^2-4x-8y-4=0$

The equation can be written as:

$x^2-4x+4-4-8y-4=0$

$(x^2-4x+4)-4-8y-4=0$

$(x-2)^2-4-8y-4=0$

$(x-2)^2=8y+8$

$(x-2)^2=8(y+1)$

$(x-2)^2=4(2)(y+1)$

Now compare the above equation with standard form of parabola is $(x - h)^2 = 4p (y - k)$, where the focus is (h, k + p).

By comparing we can concluded that h=2, p=2 and k=-1.

Therefore, the focus of the parabola is (2,1).

#Learn more

Question 4 Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x^2 = – 16y

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