Question

coordinates of two points are P(-2,5) and Q(3,5) then what is the distance of PQ​

Answer 1

Answer:

5

Step-by-step explanation:

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Answer 2

Answer:

5 units is the required distance of PQ.

Step-by-step explanation:

Explanation:

Given, coordinate of two points are P(-2,5) and Q(3,5) .

As we know,  distance formula =  $\sqrt{(x_2- x_1)^2+ (y_2 - y_1)^2}$

Step 1:

from the question we have,

$x_1 = -2 , y_ 1 = 5 , x_2 = 3\ and\ y_2 = 5$ .

Now, distance of PQ = $\sqrt{(x_2- x_1)^2+ (y_2 - y_1)^2}$

⇒ PQ = $\sqrt{(3 - (-2))^2+ (5 - 5)^2}$

⇒PQ = $\sqrt{(5 )^2 + 0}$ = $\sqrt{25}$ = 5unit

Final answer:

Hence, the distance of PQ is 5 units.

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