Copper gives two oxides.on heating 1 gram of each in hydrogen we get 0.88 and 0.789 grams of copper respectively law of multi propagation
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Ans:- Let the two oxides of Cu be named A and B.
Oxide A
Mass of Cu in 1g of oxide A = 0.888g
Mass of O in 1g of oxide A = 1-0.888 = 0.112 g
Oxide B
Mass of Cu in 1g of oxide B = 0.799g
Mass of O in 1g of oxide B = 1-0.799 = 0.201 g
In oxide A, 1 g Cu is combined with oxygen = 0.112 x 1/ 0.888 = 0.126g
In oxide B, 1 g Cu is combined with oxygen = 0.201x 1/ 0.799 = 0.252g
The different weights of oxygen combined with a fixed weight (1g) of Cu are in the ratio 0.126 : 0.252 or 1:2
This is a simple whole ratio that show the agree with the law of multiple proportions
Hope you will understand it
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