Chemistry, asked by kanu4041, 1 year ago

Copper gives two oxides.on heating 1 gram of each in hydrogen we get 0.88 and 0.789 grams of copper respectively law of multi propagation

Answers

Answered by Aseem147
6

Ans:- Let the two oxides of Cu be named A and B.

Oxide A

Mass of Cu in 1g of oxide A = 0.888g

Mass of O in 1g of oxide A = 1-0.888 = 0.112 g

Oxide B

Mass of Cu in 1g of oxide B = 0.799g

Mass of O in 1g of oxide B = 1-0.799 = 0.201 g

In oxide A, 1 g Cu is combined with oxygen = 0.112 x 1/ 0.888 = 0.126g

In oxide B, 1 g Cu is combined with oxygen = 0.201x 1/ 0.799 = 0.252g

The different weights of oxygen combined with a fixed weight (1g) of Cu are in the ratio 0.126 : 0.252 or 1:2

This is a simple whole ratio that show the agree with the law of multiple proportions

Hope you will understand it

Answered by goru7743
1

par deep Chemistry book 11th class check

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