Copper oxide was prepared by two different methods. In one case, 1.75 g of the metal gave 2.19 g of oxide. In the second case, 1.14 g of the metal gave 1.43 g of the oxide. Show that the given data illustrate the law of constant proportions.
[ Answer as per class 9 , atoms and molecules ]
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In the first method Cu : O (1.75 : 2.19) = 0.79
In the second method Cu : O (1.14 : 1.43)= 0.79
By observing these two methods we came to know that it follows law of constant proportion as the ratio of both Cu and O in copper oxide are same.
In the second method Cu : O (1.14 : 1.43)= 0.79
By observing these two methods we came to know that it follows law of constant proportion as the ratio of both Cu and O in copper oxide are same.
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