Math, asked by Prathegreat, 8 months ago

A quadratic polynomial whose zeroes are 2 and -3/ 2 is

Answers

Answered by rishithreddynelaturi
0

Answer:

when the sum and product of its zeroes are given by:

f(x)=k[x2−(sumofthezeroes)x+Productofthezeroes], where k is any non-zero constant.

∴ Required quadratic polynomial f(x) is given

by

f(x)=k[x2−(2)x−8], where k is any non-zero real constant

=k[x2−2x−8], where k is any non-zero real constant

=k[x2+(−4x+2x)−8], where k is any non-zero real constant

=k[(x2−4x)+(2x−8)], where k is any non-zero real constant

=k[x(x−4)+2(x−4)], where k is any non-zero real constant

=k[(x−4)(x+2)], where k is any non-zero real constant

The zeroes of f(x) are given by

f(x)=0

⇒(x−4)(x+2)=0

⇒x−4=0orx+2=0

⇒x=4orx=−2

Hence, the zeroes of f(x) are 4and−2.

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