Question

Copper sulphate reacts with sodium hydroxide to form a blue precipitate of
copper hydroxide and sodium sulphate. In an experiment, 15.95 g of copper
sulphate reacted with 8.0 g of sodium hydroxide to form 9.75 g of copper
hydroxide and 14.2 g of sodium sulphate. Show that this data verifies the law of conservation of mass.​

Answer 1

Answer:

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Explanation:

According to question

CuSO4 + NaOH =

(1595g) (8 g)

Clearly, in this case

الات

52

Cu(OH)2

(9.75 g)

+ Nas04

(1429)

Total mass of reactants (15.95 g 8 g) 23.95 g

Total mass of products (9.75 g+ 14.2 g) = 23.95 g

Hence, Law of conservation of mass is valid here.