Copper wire, when bent in form of square, enclosese an area of 441 cm sqaure . if the same wire is bent in form of circle, find area enclosed by it.
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swathika23:
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Let x = length of one side square
then
x^2 = 441 cm^2
x = 21
.
Perimeter of square = 4*21 = 84 cm
circumference of circle = 84 cm
2(pi)r = 84
(pi)r = 42
r= 147/11
then
x^2 = 441 cm^2
x = 21
.
Perimeter of square = 4*21 = 84 cm
circumference of circle = 84 cm
2(pi)r = 84
(pi)r = 42
r= 147/11
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