cor what value of P will the following pair of linear equation have infinitely many solutions? (p-3)x+3y, px+py=12
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(p-3)x+3y=0. Px+py=12
a1=(p-3) b1=3 c1=0
a2=p. b2=p. c2=-12
If the given equation has infinitaly many solutions then a1/a2=b1/b2=c1/c2
Now a1/a2=b1/b2
=>(p-3)/p=3/p
=>p(p-3)=3p
=>p²-6p=0 =>P(p-6)=0 =>P=6
Again b1/b2=c1/c2
=>3/p=0/-12
=>p=0
a1=(p-3) b1=3 c1=0
a2=p. b2=p. c2=-12
If the given equation has infinitaly many solutions then a1/a2=b1/b2=c1/c2
Now a1/a2=b1/b2
=>(p-3)/p=3/p
=>p(p-3)=3p
=>p²-6p=0 =>P(p-6)=0 =>P=6
Again b1/b2=c1/c2
=>3/p=0/-12
=>p=0
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