Math, asked by macman3109, 10 months ago

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Answered by priyanshudp2109
1

Step-by-step explanation:

(a)sin theta=BC/AC

sin^2 theta=(BC/AC) ^2

(b)cos theta=AB/AC

cos^2 theta=(AB/AC) ^2

(c)sin^2 theta+cos^2 theta=1

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Answered by NJD38
0

Answer:

\huge{\boxed{\boxed{\overbrace{\underbrace{\mathcal{\blue{A}\red{N}\blue{S}\red{W}\blue{E}\red{R}}}}}}}

1. sin ∅ = BC/AC

sin²∅ = BC²/AC²

2. cos ∅ = AB/AC

cos²∅ =AB²/AC²

3. sin²∅+cos²∅ = BC²/AC²+ AB²/AC²

= (AB²+BC²)/AC²

= AC²/AC² [Pythagoras Theorem]

= 1.

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