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Answer 1

Answer:

Since PQRS is a parallelogram soo PQ||RS and also PS||RQ

Therefore, for proving similarity of two triangles APR and BRP

AP=BR

PR=PR (Common)

/_APR=/_PRB (VOA)

Hence, triangle APR= triangle BRP

From similarity of triangles

AR=BP

and RA||BP

Answer 2

Step-by-step explanation:

i) In triangle APR and BRP

AP=BR (Given)

PR= PR (Common)

angle ARP= angle BPR(Alternate interior angle)

therefore,triangle APR ~=triangleBRP

ii) AR=BP (By C.P.C.T)

iii)RA||BP (By C.P.C.T)