Question

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Answer 1

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★ FORMULAE USED ★

${sin}^{2} x \: + {cos}^{2} x = 1 \\ \\ \frac{1}{cos \: x} = sec \: x \\ \\ \frac{1}{sin \: x} = cosec \: x$

★ solution ★

TAKING LHS

TAKING ∅ AS X

$sec ^{2}x + \: cosec ^{2} x \\ \\ = \frac{1}{cos ^{2}x } + \frac{1 }{sin ^{2}x } \\ \\ = \frac{sin ^{2} x + {cos}^{2} x}{ {sin}^{2}x \times {cos}^{2} x } \\ \\ = \frac{1}{ {sin}^{2} x \times {cos}^{2} x} \\ \\ = {sec}^{2} x \: {cosec}^{2} x$

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