Physics, asked by gopal5021, 9 months ago

Correct answers will be marked as brainliest... I wanna correct answers. ​

Attachments:

Answers

Answered by desaikomal551
0

Explanation:

A) the process is electrolysis

B) A process in which a chemical change, especially decomposition, is brought about by passing an electric current through a solution of electrolytes so that the electrolyte's ions move toward the negative and positive electrodes and react with them.

C) in this reation :Electrolysis of a silver nitrate solution produces oxygen at the anode and silver at the cathode. ... As stated in the introduction, most reactions at the cathode correlate well with the standard reduction potentials. Only hydrogen is produced from the electrolysis of alkali metal, alkaline earth and aluminum nitrates.

D) You would get silver at the cathode, and oxygen at the anode.

Since silver is below hydrogen in the spectrochemical series,it tends to get reduced over hydrogen, similarly, since NO3−NOX3X− is above OH−OHX− , it tends not to get oxidised, therefore giving oxygen.

Ag++e−⟶AgAgX++eX−⟶Ag (at cathode)

4OH−⟶O2+2H2O+4e‐ (at anode )

hope that was helpful pls mark me as brainliest

Answered by Kinggovind021
1

Hey mate

A) Electrolysis

B) It is the process in which a chemical change, especially decomposition, is brought about by passing an electric current through a solution of electrolytes so that the electrolyte's ions move toward the negative and positive electrodes and react with them.

C) in this reation :Electrolysis of a silver nitrate solution produces oxygen at the anode and silver at the cathode. ... As stated in the introduction, most reactions at the cathode correlate well with the standard reduction potentials. Only hydrogen is produced from the electrolysis of alkali metal, alkaline earth and aluminum nitrates.

D) We get silver at the cathode, and oxygen at the anode.

Since silver is below hydrogen in the spectrochemical series,it tends to get reduced over hydrogen, similarly, since NO3−NOX3X− is above OH−OHX− , it tends not to get oxidised, therefore giving oxygen.

Ag++e−⟶AgAgX++eX−⟶Ag (at cathode)

4OH−⟶O2+2H2O+4e‐ (at anode )

Similar questions