Physics, asked by manishgurjar11, 7 months ago

Correct equation for Ampere's circuital law for the amperian loop as shown in the figure (transvered in the direction shown by arrow marks on it)can be written as​

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Answered by anmol05200
3

Answer:

0

(I

enc

)=∮

B

ˉ

.

d

ˉ

l

Area vector of ABC is along the right direction, while ACD is along the upward direction.

Now currents passing through ABC are I

1

,I

3

along the area directions.

Now through ACD, I

2

,I

3

;I

2

along the area vector while I

3

is opposite to it.

Thus, μ

0

(I

1

+I

3

+I

2

−I

3

)=∮

B

ˉ

.

d

ˉ

l=μ

0

(I

1

+I

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