Correct equation for Ampere's circuital law for the amperian loop as shown in the figure (transvered in the direction shown by arrow marks on it)can be written as
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0
(I
enc
)=∮
B
ˉ
.
d
ˉ
l
Area vector of ABC is along the right direction, while ACD is along the upward direction.
Now currents passing through ABC are I
1
,I
3
along the area directions.
Now through ACD, I
2
,I
3
;I
2
along the area vector while I
3
is opposite to it.
Thus, μ
0
(I
1
+I
3
+I
2
−I
3
)=∮
B
ˉ
.
d
ˉ
l=μ
0
(I
1
+I
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