Question

Correct order of limiting molar conductivity of given ions in water at 298 Kis K+ > Nat > Mg2+ Mg2+ > K+ > Nat Mg2+ > Nat > K+ Na+ > K+ > Mg2+​

Answer 1

Answer:

Explanation:

298 K is for (1) Mg+2

The limiting molar conductivity of  is maximum for Mg+2 because limiting molar conductivity increases with decrease in concentration of ions.

Mg+2 has less volume which increases its ionic mobility in aqueous solution.

and therefore it has maximum Limiting molar conductivity in water among the given options.

Answer 2

Answer:

hope it's helpful marks me at brainlist

Explanation:

From Kohlrausch's law,

Molar conductivity of KCl=λo(K+)+λo(Cl−)=73.5+76.3=149.8

Molar conductivity of CaCl2=λo(Ca2+)+2×λo(Cl−)=119+(2×76.3)=271.6

Molar conductivity of K2SO4=2×λo(K+)+λo(SO42−)=2×73.5+160=307

So, limiting molar conductivity of electrolytes follow the order: KCl<CaCl2<K2SO4.