Two candles of length one feet each start burning at the same time.
One of the candles will burn down in 40hrs and the other in 24hrs. If after
H hours one of the candle has length 3 times the length of the other candle, find "H"
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Step-by-step explanation:
Let the length of both the candles be L.
Then, speed of melting of candle 1 =
5
L
speed of melting of candle 2 =
4
L
At any time, t, the length of candle 1 = L(1−
5
t
)
length of candle 2 = L(1−
4
t
)
Thus, L(1−
5
t
)=2L(1−
4
t
)
1−
5
t
=2−
2
t
10
5t−2t
=1
t=
3
10
=3
3
1
hrs.
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