Question

Corresponding sides of two similar triangles are in the ratio 2:3. If the area of smaller triangle is 48cm^2 then find the area of larger triangle.
Please find the ANS

Answer 1

Ratio of area : length:

$\dfrac {\text{Area 1}}{\text{Area 2}} = \bigg( \dfrac{\text{length 1}}{\text{length 2}}  \bigg)^2$

Find larger area:

$\dfrac {\text{48}}{\text{Area 2}} = \bigg( \dfrac{\text{2}}{\text{3}}  \bigg)^2$

$\dfrac {\text{48}}{\text{Area 2}} = \dfrac{4}{9}$

$\text {Area 2} = (48 \times 9) \div 4$

$\text {Area 2} = 108 \text { cm}^2$

Answer: The larger area is 108 cm²

Answer 2

$\huge{\ulcorner{\red{Hey\: mate}}}\rfloor$

✨ $<b>Here's ur answer$

➡️ Let the area of larger triangle be x,

Then,
✨ $\frac{area \: of \: triangle \: 1}{area \: of \: triangle \: 2} = (\frac{1st \: \: t \: length}{2nd \: t \: length} )^{2}$

✨ $\frac{48}{x} = ( \frac{2}{3} )^{2}$

✨X= $\frac{ 48 \times 9 }{4}$
$\underline{Answer =108cm}^{2}$


˙·٠•●♥[ Hope it helps you ]♥●•٠·˙