Question

Cos/1-tan+sin/1-cot=sin+cos

Answer 1

Answer:

Hey mate here's ur answer :)  

Step-by-step explanation:

LHS

= cos/1-tan + sin/1-cot

= cos/1-sin/cos + sin/1- cos/sin

= cos/cos-sin/cos + sin/sin-cos/sin    (take lcm sin , cos)

= cos²/cos-sin + sin²/sin-cos ⇒ cos² - sin²/(cos-sin)(cos-sin)

ID ⇒ a² - b² = (a+b)(a-b)

∴ (cos +sin)(cos-sin)/ (cos-sin)                       [ cancel cos-sin ]

cos+sin

LHS = RHS

hence proved !!

Hope it is helpful to u !!

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