Question

cos^2 25° + cos^2 65°) + cosec theta sec (90- theta) -cot theta tan (90-theta)​

Answer 1

We have,

cosec 25° - sec 65° = cosec (90° - 65°) - sec 65°

= sec 65°-sec 65° = 0

pls pls pls pls mark me brainlest