Question

Cos^2(π/3-x) -cos^2(π/3+x) =

Answer 1

Answer:

${ \cos }^{2} ( \frac{\pi}{3} - x) - { \cos }^{2} ( \frac{\pi}{3} + x) \\ \frac{1}{2} (2{ \cos }^{2} ( \frac{\pi}{3} - x) - 2{ \cos }^{2} ( \frac{\pi}{3} + x) ) \\ \frac{1}{2} ( \cos ( \frac{2\pi}{3} - 2x) + 1- \cos ( \frac{2\pi}{3} +2x) - 1) \\ \frac{1}{2} ( \cos ( \frac{2\pi}{3} - 2x) - \cos ( \frac{2\pi}{3} +2x) ) \\ \frac{1}{2} ( 2 \sin ( \frac{2\pi}{3} )\sin ( 2x) ) \\ \sin ( \frac{2\pi}{3} )\sin ( 2x) \\ \sin ( \pi - \frac{\pi}{3} )\sin ( 2x) \\ \sin ( \frac{\pi}{3} )\sin ( 2x) \\ ( \frac{ \sqrt{3} }{2} )\sin ( 2x) \\ you \: can \: end \: up \: here... \\ \\ or \: you \: can \: add \: 2 \: lines \: more \: if \: it \: is \: asked \: in \: \: question \: paper.\\ \frac{ \sqrt{3} }{2} \times 2 \sin(x) \cos(x) \\ \sqrt{3} \sin(x) \cos(x)$