Math, asked by shruti223, 1 year ago

cos^2(45+theta)+cos^2(45-theta)/tan(60+theta)tan(30-theta)

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Answered by aslamalikumazalea

· cos2(45 + theta) + cos2(45 - theta) / tan(60 + theta) tan(30 - theta) = 1. LHS =cos2(45 + theta) + sin2{90 - (45 -theta)} / tan( 60 + theta) cot{90 - (30 - theta ...

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