Question

(cos^2 -sin^2)/sin.cos=(1-tan^2)/tan

Answer 1

Step-by-step explanation:

this is proved that left hand side = right hand side

Answer 2

Answer:

(1-tan^2A)/tanA

Step-by-step explanation:

(cos^2A- sin^2A)/sinAcosA

divide numerator and denominator by cos^2A

((cos^2A/cos^2A)-(sin^2A/cos^2A))/(sinAcosA/cos^2A)

(1-tan^2A)/(sinA/cosA)

(1-tan^2A)/(tanA)