Question

cos ( 2 sin inverse x) = 1/9

Answer 1

HEYA !

Given that,

cos ( 2 sin ̄¹ x ) = 1/9

Using Formula ,
{ cos 2θ = 1 − 2sin²θ }

We get

1 − 2 sin² ( sin ̄¹ x ) = 1/9

− 2 [ sin ( sin ̄¹ x ) ]² = 1/9 − 1

− 2 ( x )² = (1 − 9) / 9

− 2x² = − 8/9

→ x² = 8 / (9×2)

→ x² = 4/9

→ x = √ (4/9)

$\Rightarrow \boxed{ \text{x} = \pm \: \frac{2}{3} } \: \: \: \: \: \: \: \textbf{Ans.}$

Answer 2

Answer:

i hope it helps u.....