cos ^2 thita -cos^4 thita
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Answered by
1
Answer:
cos²theta × sin²theta
this is the answer
Answered by
1
Answer:
Cos²ø Sin²ø
Step-by-step explanation:
LET Ø BE THETA
Cos²ø — Cos⁴ø
Cos²ø ( 1 — Cos²ø)
Cos²ø [ 1 — (1 — Sin²ø)]
Cos² ø ( 1 — 1 + Sin²ø)
Cos²ø ( Sin²ø)
Cos²ø Sin²ø
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