Question

If a pole 6 m high casts a shadow 2√3 m long on the ground, then the elevation of the sun is?? ​

Answer 1

Answer:

If a pole 6 m high casts a shadow 2√3 m long on the ground, then the elevation of the sun is

$tan \alpha = \frac{p}{b} = \frac{6}{2 \sqrt{ 3} } = \sqrt{3} = {60}^{o}$