Question

cos[2cos^-1(1/3) + sin^-1(1/3)] = ?

Answer 1

Sin^-1(1/3)=pi/2-cos^-1 (1/3)
So eqn becomes cos of cos inverse 1/3 +pi/2
Then solve cos of theta + pi/2
Where cos theta=1/3 this will be equal ti -2root2/3
So ans will be cos cos inverse -2root2/3
=pi -cos inverse 2root2 by 3


Hope it helps