cos(2x+π/4)-cos2x=0
Please help me
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can u plz explain the question ? i mean what is the demand of the question ?
fisijapahj2u:
Solve the equation
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1/√2cos2x - 1/√2Sin2x = cos 2x
-1/√2Sin2x = cos2x(1-1/√2)
tan2x = -√2(1-1/√2)
-1/√2Sin2x = cos2x(1-1/√2)
tan2x = -√2(1-1/√2)
Result should be 1/16(8k-1)π
how could you introduce k here of its not given in question
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