cos^3 teta-cos3teta÷cos teta+sin^3teta +sin3teta÷sin teta=3
Answers
Answered by
2
Step-by-step explanation:
cos³A-cos3A/cosA+sin³A+sin3A/sinA
=cos³A-4cos³A+3cosA/cosA +sin³A+3sinA-4sin³A/sinA
=3cosA-3cos³A/cosA+3sinA-3sin³A/sinA
=3cosA(1-cos²A)/cosA +3sinA(1-sin²A)/sinA
=3sin²A+3cos²A
=3
Answered by
0
Answer:
Step-by-step explanation:
cos³A-cos3A/cosA+sin³A+sin3A/sinA
=cos³A-4cos³A+3cosA/cosA +sin³A+3sinA-4sin³A/sinA
=3cosA-3cos³A/cosA+3sinA-3sin³A/sinA
=3cosA(1-cos²A)/cosA +3sinA(1-sin²A)/sinA
=3sin²A+3cos²A
=3
Similar questions
Hindi,
6 months ago
India Languages,
6 months ago
Math,
1 year ago
Hindi,
1 year ago
Physics,
1 year ago