cos 3 theta-2 cos 4 theta/sin 3 theta+2 sin 4 theta where theta=150
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[cos(2∅) - 2cos(4∅)]÷[sin3∅ + 2sin4∅]
∅=150
= [cos450 - 2cos600]÷[sin450 + 2sin600]
= [cos90 - 2cos120]÷[sin90 - 2sin120]
= [0 - 2(-1/2)]÷[1 - √3]
=1/(1-√3)
= -1/2 - √3/2
or = -(1+√3)/2
hope it helps you
@di
∅=150
= [cos450 - 2cos600]÷[sin450 + 2sin600]
= [cos90 - 2cos120]÷[sin90 - 2sin120]
= [0 - 2(-1/2)]÷[1 - √3]
=1/(1-√3)
= -1/2 - √3/2
or = -(1+√3)/2
hope it helps you
@di
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