Math, asked by shrishtii17, 1 year ago

find the largest number which divides 615 and 963 leaving the remainder 6 in each case

Answers

Answered by Anonymous
5
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Solution :-

To find the largest number which divides 615 and 963 leaving the remainder 6 in each case

Subtract the remainder from both Numbers.

We get ( 615 - 6) ( 963 - 6)

609 & 958

Find the HCF of Both ( 609 & 963)

So, the greatest value of 'm' signifies the greatest common divisor of (609, 957).

609 = 3*7*29

957 = 3*11*29

GCD (609, 957) = 3*29 = 87 

Her The m Is the greatest Number divisible by both

Hop it helps.

Regards ♡♡《 Nitish kr 》♡♡

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Answered by SyedNomanShah
2

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