Math, asked by Aditicat, 1 year ago

cos^3A+sin^3A/cosA+sinA+cos^3Asin^3A/cosAsinA

Answers

Answered by bhagatpriyanshu1

LHS = cos3A + sin3A(cos A + sin A) + cos3A − sin3A(cos A − sin A)(cos A+sin A)(cos2A+sin2A−cos A . sin A)(cos A+sin A) + (cos A−sin A)(cos2A+sin2A+cos A . sin A)(cos A−sin A)=(cos2A+sin2A−cos A . sin A) + (cos2A+sin2A+cos A . sin A)=1 −cos A . sin A + 1+ cos A . sin A=2=RHS

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