cos 3x + cos x - cos 2x = 0
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We have,
cos3x + cosx - cos2x = 0
Or 2cos(3x+x/2)cos(3x-x/2)-cos2x =0
Or 2cos2xcosx - cos2x =0
Or cos2x(2cosx-1) =0
So,
cos2x=0 or 2cosx-1=0
Or 2cosx = 1
Or cosx = 1/2
Or cosx = cos60° or cosπ/3
Or x = 60° or π/3
cos3x + cosx - cos2x = 0
Or 2cos(3x+x/2)cos(3x-x/2)-cos2x =0
Or 2cos2xcosx - cos2x =0
Or cos2x(2cosx-1) =0
So,
cos2x=0 or 2cosx-1=0
Or 2cosx = 1
Or cosx = 1/2
Or cosx = cos60° or cosπ/3
Or x = 60° or π/3
Aryan4231:
Thank you but find general solution of this question
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