Question

(cos 42° cosec 48°) - (sin 15° sec 75°)​

Answer 1

Anok I have doneexplanati

Answer 2

Answer:

(cos42 cosec48) -(sin15sec75)

(cos42 sec(90-48)) -(sin15 cosec(90-75))

(cos42 sec42) - (sin15 cosec15)

(cos42/cos42) - (sin15/sin15)

(1) - (1)

0

hope it helps u.....^_^