Physics, asked by yadavsd5034, 6 months ago

cos 45/sec 30+cosec 30

Answers

Answered by likitha72
1

Answer:

Answer:

\begin{gathered}Value \: of \:\frac{cos45}{(sec30+cosec30)}\\=\frac{\sqrt{6}(\sqrt{3}-1)}{8}\end{gathered}

Valueof

(sec30+cosec30)

cos45

=

8

6

(

3

−1)

Step-by-step explanation:

Value \: of \:\frac{cos45}{(sec30+cosec30)}Valueof

(sec30+cosec30)

cos45

=\frac{\frac{1}{\sqrt{2}}}{\frac{2}{\sqrt{3}}+2}=

3

2

+2

2

1

=\frac{\frac{1}{\sqrt{2}}}{\frac{2+2\sqrt{3}}{\sqrt{3}}}=

3

2+2

3

2

1

=\frac{1}{\sqrt{2}}\times \frac{\sqrt{3}}{2(1+\sqrt{3})}=

2

1

×

2(1+

3

)

3

=\frac{\sqrt{2}}{\sqrt{2}\times \sqrt{2}} \times \frac{\sqrt{3}\times (\sqrt{3}-1)}{2(\sqrt{3}+1)(\sqrt{3}-1)}=

2

×

2

2

×

2(

3

+1)(

3

−1)

3

×(

3

−1)

=\frac{\sqrt{6}(\sqrt{3}-1)}{4(\big(\sqrt{3}\big)^{2}-1^{2})}=

4((

3

)

2

−1

2

)

6

(

3

−1)

=\frac{\sqrt{6}(\sqrt{3}-1)}{4(3-1)}=

4(3−1)

6

(

3

−1)

=\frac{\sqrt{6}(\sqrt{3}-1)}{8}=

8

6

(

3

−1)

Therefore,

\begin{gathered}Value \: of \:\frac{cos45}{(sec30+cosec30)}\\=\frac{\sqrt{6}(\sqrt{3}-1)}{8}\end{gathered}

Valueof

(sec30+cosec30)

cos45

=

8

6

(

3

−1)

•••♪

Answered by durveshkpatil1001
0

Answer:

5/2√6

Explanation:

1/√2/√3/2+1/2=5/2√6

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