Math, asked by bvm754455, 10 months ago

cos^4alpha+2cos^2alpha×1-1/sec^2alpha

Answers

Answered by VKRohan

0

follow me for answer fast

Answered by MH99

1

Answer:

cos²α(cos²α+1)

Step-by-step explanation:

cos⁴α+2cos²α×1– 1/sec²α

=> cos⁴α+2cos²α–cos²α [1/sec²α=cos²α]

=> cos⁴α+cos²α

=> cos²α (cos²α+1)

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