cos 510x cos 330+sin 390x cos 120 please slove these maths
Answers
Answered by
1
Hi ,
1 ) cos 510 = cos ( 360 + 150 )
= cos 150
= cos ( 180 - 30 )
= - cos 30
2 ) cos 330 = cos ( 360 - 30 )
= cos 30
3 ) sin 390 = sin ( 360 + 30 )
= sin 30
4 ) cos 120 =cos ( 90 + 30 )
= - sin 30
NOw ,
cos 510 cos 330 + sin 390 cos 120
= ( - cos 30 ) cos 30 + sin 30 ( - sin 30 )
= - cos² 30 - sin² 30
= - ( cos² 30 + sin² 30 )
= -1 [ ∵ sin² A + cos² A = 1]
I hope this helps you.
: )
1 ) cos 510 = cos ( 360 + 150 )
= cos 150
= cos ( 180 - 30 )
= - cos 30
2 ) cos 330 = cos ( 360 - 30 )
= cos 30
3 ) sin 390 = sin ( 360 + 30 )
= sin 30
4 ) cos 120 =cos ( 90 + 30 )
= - sin 30
NOw ,
cos 510 cos 330 + sin 390 cos 120
= ( - cos 30 ) cos 30 + sin 30 ( - sin 30 )
= - cos² 30 - sin² 30
= - ( cos² 30 + sin² 30 )
= -1 [ ∵ sin² A + cos² A = 1]
I hope this helps you.
: )
Similar questions