Question

cos^{6}A+sin^6A=1÷4(1+3cos^2A)

Answer 1

Answer:

cos^6 A+sin^6 A  

=(cos^2 A)^3+(sin^2 A)^3

=(cos^2 A+sin^2 A)(cos^4 A+sin^4 A−cos^2 A sin^2 A)

=1⋅[(cos^2 A+sin^2 A)^2−3cos^2 A sin^2 A]

=1 −  3(sin2 A)^2 / 4  

=4−3(1−cos^2 A) / 4

=1+cos^2 2 A / 4

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Step-by-step explanation:

Answer 2

Answer:

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