Question

(cos^6+sin^6)+3sin^2cos^2

Answer 1

you can see your answer

Answer 2

Hi ,

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1 ) a³ + b³ = ( a + b ) ( a² - ab + b² )

= ( a + b ) [ ( a + b )² - 3ab ]

2 ) cos²x + sin² x = 1

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cos^6 x+ sin^6x + 3sin²xcos²x

= ( cos²x )³ + ( sin²x )³ + 3sin²xcos²x

= (cos²x+sin²x)[(cos²x+sin²x)² -3sin²xcos²x]+3cos²xsin²x

= 1 - 3cos²xsin²x + 3cos²xsin²x

= 1

I hope this helps you.

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