Question

divide rs. 3000 in three parts in such way that one third of the 1st part ,one fifth of 2nd part and one seventh of 3rd part are equal.

Answer 1

Algebra,

We have
R.S. 3000,
have to divide in three parts in such way that one third of the 1st part, one fifth of 2nd part and one seventh of 3rd part be equal.

Let the three parts be x, y and z respectively.

A.T.Q.

1/3 × x = 1/5 × y = 1/7 × z

Now,

1/3 × x = 1/5 × y and 1/3 × x = 1/7 × z

or, 5/3 × x = y or, 7/3 × x = z

So, x + y + z = 3000

or, x + 5/3x + 7/3x = 3000

or, (3x + 5x + 7x)/3 = 3000

or, 15x = 9000

or, x = 9000/15

or, x = 600

Therefore y = 5/3 × 600

=1000

and z = 7/3 × 600
= 1400

Let's have a quick cheak,

x + y + z
= 600 + 1000 + 1400
= 3000

That's it
Hope it helped ლ(´ڡ`ლ)