Math, asked by amulyabhukya08, 9 months ago

(cos^6 theta +sin^6theta)+3sin^2 theta cos^2theta =?​

Answers

Answered by ranasumita567
1

Answer:

sorry can't understand your question properly

Answered by mritunjayy
0

Answer:

sin

6

θ+cos

6

θ+3sin

2

θcos

2

θ

⇒LHS=(sin

2

θ)

3

+(cos

2

θ)

3

+3sin

2

θcos

2

θ

Using, [a

3

+b

3

=(a+b)

3

−3ab(a+b)]

⇒LHS=(sin

2

θ+cos

2

θ)

3

−3sin

2

θcos

2

θ(sin

2

θ+cos

2

θ)

3

+3sin

2

θcos

2

θ

⇒LHS=1−3sin

2

θcos

2

θ+3sin

2

θcos

2

θ=1=RHS

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