(cos^6a+sin^6a)+3sin^2a.cos^2a=
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cos^6a+sin^6a+3sin^2a.cos^2a
now make it into a +b whole cube formula
(cos^2a)3+(sin^2a)3+3sin^2a.cos^2a (sin^2a+cos^2a)..........a^3+b^3+3ab (a+b)
=(cos^2a+sin^2a)^3
=(1)^3
=1
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